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MATLAB毕业设计

转向梯形优化设计matlab程序

时间:2020/10/13 22:25:32  作者:  来源:  查看:0  评论:0
内容摘要: 优化计算MATLAB程序首先,将目标函数写成M文件,其程序语句如下;function f = fun (x)global K L thetamax alphafor i=1:61f = 0betae = atan(tan(alpha(i)/(1-(K/L)*tan(alp...

优化计算MATLAB程序

首先,将目标函数写成M文件,其程序语句如下;

function f = fun (x)

global K L thetamax alpha

for i=1:61

f = 0

betae = atan(tan(alpha(i)/(1-(K/L)*tan(alpha(i))));

A(i)=2*x(1).^2*sin(x(2)+alpha(i));

B(i)=2*K*x(1)-2*x(1).^2*cos(x(2)+alpha(i));

C(i)=2*x(1).^2-4*x(1).^2*(cos(x(2)).^2+4*K*x(1)*cos(x(2))-2*K*x(1)*cos(x(2)+alpha(i));

theta3(i)= 2*acot((A(i)+sqrt(A(i).^2+B(i).^2-C(i).^2))/(B(i)+C(i)));

beta(i)=x(2)+theta3(i)-pi;

if alpha(i)<=pi/18

f(i)=1.5*abs(beta(i)-betae3(i));

elseif alpha>=pi/18,alpha(i)<=pi/9;f(i)=abs(betaa(i)-betae3(i));

elsef(i)=0.5*abs(beta(i)-betae3(i));

global K L thetamax alpha

K=input

L=input

thetamax=input

x0(1)=input

x0(2)=input

thetamax = thetamax*pi/180;

x0(2)=x0(2)*pi/180;lb(1)=0.17K; lb(2)=0.17*K; ub(1)=acot(K/(1.2*L))

ub(2)=pi/2;

alpha=linspace (0, theamax ,61);

lb=[lb(1),lb(2)];

ub=[ub(1),ub(2)];x(0)=[x0(1),x0(2)];

options = optimset ( ‘TolFun’,‘le-10’,‘TolCon’,‘le-6’)

[x,resnorm] = lsqnonlin(fun,x0,lb,ub,options)

g lobal K L thetamax alpha

K = input

L= input

 thetamax= input

x ( 1) = input

x ( 2) = input

thetamax = thetamax * pi/ 180;

x ( 2) = x ( 2) * pi/ 180;

alpha= linspace( 0, thetamax , 61) ;

 fo r i= 161

   betae= atan( tan( alpha( i) ) / (( 1- K/ L) * tan( alpha( i) ) ) ) ;

A ( i) = 2* ( x ( 1) ) .2* sin ( x ( 2) + alpha( i) ) ;

B( i) = 2* K* x( 1) - 2* ( x ( 1) ) . 2* cos( x( 2) + alpha( i) ) ) ;

C ( i ) = 2* ( x ( 1) ) . 2- 4 * ( x ( 1) ) . 2*( cos( x( 2) ) ) . 2+ 4* K * x ( 1) * cos( x ( 2) ) - 2* K* x ( 1) * cos( x ( 2) + alpha( i) ) ;

theta3(i)= 2* acot ( A( i) + sqr t ( ( ( A( i) ) .2+( B( i) ) . 2- * ( C( i) ) . 2) ) /( B( i) + C( i) ) ) ;

beta( i) = x ( 2) + theta3( i) - pi;

end

plot ( alpha( i) , betae( i ) ,r);

hold  on

plot ( alpha ( i) , beta( i) ,b)

hold o ff

  


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